A clerk notes the arithmetic sequence 7, 11, 15, … What is the 15th term of this sequence?
एक क्लर्क ने समांतर (Parallel) अनुक्रम 7, 11, 15, … लिखा। इस अनुक्रम का 15वाँ पद क्या है?
Answer और ExplanationAnswer and explanation
Answer: (A) 63
अनुक्रम (Sequence) 7, 11, 15, … है
a = 7, d = 11 − 7 = 4, n = 15
T15 = a + (n − 1)d = 7 + 14 × 4
= 7 + 56 = 63
✓
15वाँ पद (Term) 63 है।
The sequence is 7, 11, 15, …
a = 7, d = 11 − 7 = 4, n = 15
T15 = a + (n − 1)d = 7 + 14 × 4
= 7 + 56 = 63
✓
The 15th term is 63.
SMART APPROACH
यहाँ हर पद (Term) (4 का गुणज (Multiple)) + 3 है: 7 = 4 + 3, 11 = 8 + 3। तो Tn = 4n + 3 और T15 = 60 + 3 = 63। यह रूप याद रखें: सार्व अंतर (Common difference) d वाली हर AP में Tn = dn + (a − d) होता है।
Every term here is (a multiple of 4) + 3: 7 = 4 + 3, 11 = 8 + 3. So Tn = 4n + 3 and T15 = 60 + 3 = 63. Remember this form: an AP with common difference d always has Tn = dn + (a − d).
Source: DP AWO/TPO · 16 Jan 2026 · Shift 2। Solution: Prashant Sir, Vijayastra।Source: DP AWO/TPO · 16 Jan 2026 · Shift 2. Solution by Prashant Sir, from Vijayastra.