SSC Steno10 Sep 2026Shift 1Series (Number, Letter and Mixed)

If 12 Δ 4 = 48, 18 Δ 3 = 54 and 8 Δ 10 = 80, then find the value of (15 Δ 4) + (20 Δ 2).

यदि 12 Δ 4 = 48, 18 Δ 3 = 54, और 8 Δ 10 = 80, तो (15 Δ 4) + (20 Δ 2) का मान ज्ञात कीजिए।

Answer और ExplanationAnswer and explanation

Answer: (A) 100

1
Pattern यह है कि a Δ b = a × b है, क्योंकि 12 × 4 = 48, 18 × 3 = 54 और 8 × 10 = 80 है।
2
15 Δ 4 = 15 × 4 = 60 और 20 Δ 2 = 20 × 2 = 40 होगा।
3
दोनों का sum = 60 + 40 = 100 है।
✓
उत्तर (a) 100 है।
1
The pattern is a Δ b = a × b, since 12 × 4 = 48, 18 × 3 = 54 and 8 × 10 = 80.
2
15 Δ 4 = 15 × 4 = 60 and 20 Δ 2 = 20 × 2 = 40.
3
Sum = 60 + 40 = 100.
✓
The answer is (a) 100.

Source: SSC Steno · 10 Sep 2026 · Shift 1। Solution: Prashant Sir, Kavach।Source: SSC Steno · 10 Sep 2026 · Shift 1. Solution by Prashant Sir, from Kavach.