Selection Post Phase XIV (12th)23 Sep 2026Shift 2Trigonometry

Simplify 1 − sin²θcos²θ, where cos θ ≠ 0.

1 − sin²θcos²θ को सरल कीजिए, जहाँ cos θ ≠ 0 है।

Answer और ExplanationAnswer and explanation

Answer: (C) 1

सर्वसमिका (Identity) sin²θ + cos²θ = 1 से 1 − sin²θ = cos²θ मिलता है।
1 − sin²θcos²θ = cos²θcos²θ = 1
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उत्तर 1 है।
From sin²θ + cos²θ = 1, we get 1 − sin²θ = cos²θ.
1 − sin²θcos²θ = cos²θcos²θ = 1
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The answer is 1.

Source: Selection Post Phase XIV (12th) · 23 Sep 2026 · Shift 2। Solution: Prashant Sir, Vijayastra।Source: Selection Post Phase XIV (12th) · 23 Sep 2026 · Shift 2. Solution by Prashant Sir, from Vijayastra.