In a certain code language: ·AB→A>B ·A#B→A<B ·A$B→A=B Given: X @ Y # Z $ W. Which conclusion is correct?
एक निश्चित कू ट भाषा में: ·AB→A>B ·A#B→A<B ·A$B→A=B दिया गया है: X @ Y # Z $ W. कौन-सा निष्कर्ष सही है?
Answer और ExplanationAnswer and explanation
Answer: (C) X > Y, Z = W, and Y < Z
व्यंजक X @ Y # Z $ W का अर्थ: •XY→X>Y •Y#Z→Y<Z •Z$W→Z=W अतः X > Y, Z = W, and Y < Z सही है।
Decoding X @ Y # Z $ W: •XY→X>Y •Y#Z→Y<Z •Z$W→Z=W Hence, X > Y, Z = W, and Y < Z is correct.
Source: SSC Selection Post (12th) · 18 Sep 2026 · Shift 2। Solution: Prashant Sir, Kavach।Source: SSC Selection Post (12th) · 18 Sep 2026 · Shift 2. Solution by Prashant Sir, from Kavach.