If sec²A + cosec²A = 13 and A is an acute angle, then find the value of tan²A + cot²A.
यदि sec²A + cosec²A = 13 है, तथा A एक न्यून कोण (Angle) है, तो tan²A + cot²A का मान ज्ञात कीजिए।
Answer और ExplanationAnswer and explanation
Answer: (B) 11
sec²A = 1 + tan²A और cosec²A = 1 + cot²A
(1 + tan²A) + (1 + cot²A) = 13
tan²A + cot²A = 13 − 2 = 11
✓
मान 11 है।
sec²A = 1 + tan²A and cosec²A = 1 + cot²A
(1 + tan²A) + (1 + cot²A) = 13
tan²A + cot²A = 13 − 2 = 11
✓
The value is 11.
Source: RRB Group D · 10 Feb 2026 · Shift 3। Solution: Prashant Sir, Vijayastra।Source: RRB Group D · 10 Feb 2026 · Shift 3. Solution by Prashant Sir, from Vijayastra.