Selection Post Phase XIV (10th)24 Sep 2026Shift 3Simplification and Approximation

Simplify using BODMAS: [18 ÷ 6 + (4 − 3)] × 5 − 2

BODMAS का उपयोग करके सरल करें : [18 ÷ 6 + (4 − 3)] × 5 − 2

Answer और ExplanationAnswer and explanation

Answer: (D) 18

छोटा कोष्ठक (Bracket): (4 − 3) = 1
बड़ा कोष्ठक: 18 ÷ 6 + 1 = 3 + 1 = 4
व्यंजक (Expression) = 4 × 5 − 2 = 20 − 2 = 18
✓
उत्तर 18 है।
Small bracket: (4 − 3) = 1
Square bracket: 18 ÷ 6 + 1 = 3 + 1 = 4
Expression = 4 × 5 − 2 = 20 − 2 = 18
✓
The answer is 18.

Source: Selection Post Phase XIV (10th) · 24 Sep 2026 · Shift 3। Solution: Prashant Sir, Vijayastra।Source: Selection Post Phase XIV (10th) · 24 Sep 2026 · Shift 3. Solution by Prashant Sir, from Vijayastra.