Selection Post Phase XIV (10th)25 Sep 2026Shift 3Indices and Surds

Simplify using BODMAS: 212 − 42 + √529 − (19 + 20)

BODMAS का प्रयोग करके सरल कीजिए: 212 − 42 + √529 − (19 + 20)

Answer और ExplanationAnswer and explanation

Answer: (C) 409

पहले कोष्ठक (Bracket): 19 + 20 = 39
फिर घात (Power) और मूल: 212 = 441, 42 = 16, √529 = 23
मान = 441 − 16 + 23 − 39 = 409
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उत्तर 409 है।
Bracket first: 19 + 20 = 39
Powers and root: 212 = 441, 42 = 16, √529 = 23
Value = 441 − 16 + 23 − 39 = 409
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The answer is 409.

Source: Selection Post Phase XIV (10th) · 25 Sep 2026 · Shift 3। Solution: Prashant Sir, Vijayastra।Source: Selection Post Phase XIV (10th) · 25 Sep 2026 · Shift 3. Solution by Prashant Sir, from Vijayastra.