The data given below shows the marks obtained by 10 different students in an examination: 36, 91, 80, 77, 64, 80, 45, 56, 41, 96. Find the median of the marks received by the 10 students.
नीचे दिया गया डेटा एक परीक्षा में 10 अलग-अलग छात्रों द्वारा प्राप्त अंकों को दर्शाता है: 36, 91, 80, 77, 64, 80, 45, 56, 41, 96। 10 छात्रों द्वारा प्राप्त अंकों की माध्यिका (Median) ज्ञात कीजिए।
Answer और ExplanationAnswer and explanation
Answer: (A) 70.5
आरोही क्रम (Ascending order) में: 36, 41, 45, 56, 64, 77, 80, 80, 91, 96
n = 10 (सम), तो माध्यिका (Median) = 5वें और 6ठे मान (Value) का औसत (Average)
माध्यिका = 64 + 772 = 1412 = 70.5
✓
माध्यिका 70.5 है।
In ascending order: 36, 41, 45, 56, 64, 77, 80, 80, 91, 96
n = 10 (even), so median = average of the 5th and 6th values
Median = 64 + 772 = 1412 = 70.5
✓
The median is 70.5.
Source: Selection Post Phase XIV (Graduate) · 29 Jul 2025 · Shift 3। Solution: Prashant Sir, Vijayastra।Source: Selection Post Phase XIV (Graduate) · 29 Jul 2025 · Shift 3. Solution by Prashant Sir, from Vijayastra.